Question

From a solid right circular cylinder with height 10cm and radius of the base 6 cm, a right circular cone of the same height and base is removed. Find the volume of the remaining solid. ​also find the whole surface area. T.S.A

Answer 1

TSA of remaining solid = TSA of cylinder - TSA of cone
= 2πr(r+h) - πr(r+l)
= πr(2r + 2h - r + l)
=22 / 7 × 6 ( 20+6+11.66)
=22 / 7 × 6 × 37.66
=710.16cm^2
volume of remaining solid = Volume of Cylinder - volume of cone
=πr^2h - 1/3πr^2h
=2 /3πr^2h
=2 /3×22 /7×6×6×10
=753.6cm^3

Answer 2

Answer:

Step-by-step explanation:

TSA of remaining solid = TSA of cylinder - TSA of cone = 2πr(r+h) - πr(r+l)  = πr(2r + 2h - r + l)  =22 / 7 × 6 ( 20+6+11.66) =22 / 7 × 6 × 37.66 =710.16cm^2 volume of remaining solid = Volume of Cylinder - volume of cone  =πr^2h - 1/3πr^2h  =2 /3πr^2h=2 /3×22 /7×6×6×10=753.6cm^3

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