Question

from a solid right circular cylinder with height 12cm and radius of base 5cm. a right circular cone of same height and same radius is removed. find the volume and TSA of remaining solid​

Answer 1

Answer:

$volume \: of \: cylinder \: = \pi {r}^{2} h = \frac{22}{7} \times 5 \times 5 \times 12 = 942.85714 {cm}^{2}$

$volume \: of \: cone = \frac{1}{3} \pi {r}^{2} h = \frac{1}{3} \times \frac{22}{7} \times 5 \times 5 \times 12 = 314.28571 {cm}^{2}$

volume of remaining portion = volume of cylinder- volume of cone

942.85714 -314.28571=628.57143

slant height of cone = 12^2+5^2=144+25=169 =13

area of remaining portion = csa of cylinder +base area +csa of cone

$2 \times \frac{22}{7} \times 5 \times 12 - \frac{22}{7} \times 5 \times 13 \\377.14 + 47.14 \\ 424.28$