Question

from a solid right circular cylinder with height 15 cm and radius 7 cm, a right circular cone of the same height and base is removed. find the volume of remaining solid ​

Answer 1

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volume of cylinder = pie x r2 x h.

= 22 / 7 x 7 x 7 x 15

= 2310 cm3.

Volume of cone = 1/3 x pie x r2 x h

= 1/3 x 22/7 x 7 x 7 x 15

= 770 cm3.

Volume of remaining solid = volume of cylinder - volume of the cone

= 2310 - 770 = 1540 cm3.

Thus the volume of remaining solid = 1540 cm3.

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Answer 2

Given:-

• From a solid right circular cylinder with height 15 cm and radius 7 cm, a right circular cone of the same height and base is removed.

To Find:-

• Volume of the remaining solid.

Solution:-

For Cylinder,

We are given with the dimensions as:-

• Height = 15 cm
• Radius = 7 cm

We know,

• Volume of cylinder = πr²h cu.units

Hence,

Volume of cylinder = 22/7 × (7)² × 15

Volume = 22/7 × 49 × 15

Volume = 22 × 7 × 15

Volume = 2310 cm³

∴ Volume of the cone is 2310 cm³.

For Cone,

We are give with the dimensions of cone as:-

• Height = 15 cm
• Radius = 7 cm

We know,

• Volume of cone = 1/3 πr²h cu.units

Hence,

Volume of cone = 1/3 × 22/7 × (7)² × 15

Volume = 1 × 22/7 × 49 × 5

Volume = 22 × 7 × 5

Volume = 770 cm³

∴ Volume of the cone is 770 cm³.

Now,

Volume of remaining solid is as follows:-

Volume of cylinder - Volume of cone

= 2310 - 770

= 1540 cm³

∴ Volume of the remaining solid is 1540 cm³.

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