from a station 'x' a train starts from rest and attains a speed of 54km/hr in 10s, then with this uniform speed it moves for 8 min and then by applying break it stops 'y' in 6 s.find the distance between the station 'x' and station ' y'
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velocity =54 km/hr=15m/s
distance travelled in 10s=150 m
distance travelled in next 8min=15×8×60=7200 m
stopping distance =u²/2g=15×15/2×10=11.2m
therefore total distance covered =7211.2m=7.2112km
distance travelled in 10s=150 m
distance travelled in next 8min=15×8×60=7200 m
stopping distance =u²/2g=15×15/2×10=11.2m
therefore total distance covered =7211.2m=7.2112km
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