Question

From a steel wire of density r is suspended a brass block of
density ⍴b. The extension of steel wire comes to e. If the
brass block is now fully immersed in a liquid of density ⍴l,
the extension becomes e'. The ratio e'/e will be
(a) ⍴b/⍴b - ⍴l
(b) ⍴b - ⍴l/⍴b
(c) ⍴b - ⍴/⍴l - ⍴
(d) ⍴l/⍴b - ⍴l

Answer 1

Answer:

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By: Tamilini