Question

From a steel wire of density rho is suspended a
brass block of densityrho????.The extension of steel
wire comes to e. If the brass block is now fully
immersed in a liquid of density rl, the extension
becomes e'. The ratio e will be
e'
(a) rho???? (b) rho???? - rho????
rho???? - rho???? rho????
b
(c) rho???? - rho (d) rho????
rho???? - rho rho???? - rho????

Answer 1

Answer:

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Answer 2

Since everything else (L,A,Y) is kept constant, extension will be directly proportional to the Force, which is mg or ρbVg

After immersing, tension will reduce due to buoyant force and will become ρbVg−ργVg

Thus, ee′=ρbVgρbVg−ργVg=ρbρb−ργ