Math, asked by Anonymous, 12 days ago

From a team of 15 players 6 are bowlers 7 are batsmen, 2 are wicket keeper. Find the number of ways to form a team fo 11 players having at least 4 bowlers 5 batsmen and 1 wicket keeper.

Answer is 537 I need full solution

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Answers

Answered by divyasingh016787
1

Answer:

Let B stand for bowler, W for wicket-keeper and O for others. Thus we have B (4), W (2), O (10). Now we have to keep in mind the restrictions of at least 3 bowlers so that there could be either 3 or 4 bowlers, at least one wicket-keeper, so that there could be either 1 or 2 wicket-keepers.

B(4) W(2) O(10)

3174C3⋅2C1⋅10C7=960 </p><p>3264C3⋅2C2⋅10C6=8404164C4⋅2C1⋅10C6=4204254C4⋅2C2⋅10C5=252

hope it will help you

Answered by MathTeacher029
0

Answer is: 537 15 : Players 6 : Bowlers 7 : Batsman 2

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