Question

From a team of 6 students, in how many ways can we choose a captain and vice-captain assuming one person can not hold more than one position?​

Answer 1

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$\Large\fbox{\color{purple}{QUESTION}}$

From a team of 6 students, in how many ways can we choose a captain and vice-captain assuming one person can not hold more than one position?

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$\Large\fbox{\color{purple}{ SOLUTION }}$

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➡️From a team of 6 students, two students are to be chosen in such a way that one student will hold only one position.

➡️Here, the no. of ways of choosing a captain and vice-captain is the permutation of 6 different things taken 2 at a time.

➡️So, 6^P2 = 6! / ( 6 -2 )! = 6! / 4! = 2! = 2

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Answer 2

Answer:

➡ SOLUTION:-

➡️From a team of 6 students, two students are to be chosen in such a way that one student will hold only one position.

➡️Here, the no. of ways of choosing a captain and vice-captain is the permutation of 6 different things taken 2 at a time.

➡️So, 6^P2 = 6! / ( 6 -2 )! = 6! / 4! = 2! = 2✔

Step-by-step explanation:

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