Question

from a top of pillar which is 35m high above the water the angle oddepression of a boat is 45 degrees.find the horizontal distance of the boat from the pillar​

Answer 1

Answer:

$\boxed{\red{\sf Distance_{(Horizontal)}= 35m }}$

Step-by-step explanation:

Given that , a pillar is 35m high , above the water. And the angle of depression of a boat observed from the top of the pillar is 45° . We need to find out the horizontal distance of the boat from the pillar . For the diagram refer to attachment.

From the diagram :-

$\sf\dashrightarrow \angle BCD =\angle CBA$

• They are equal since they are alternate interior angles. Therefore ,

$\sf\dashrightarrow \angle CBA = 45^{\circ}$

Let us take the horizontal distance be x . We know that tanθ = perpendicular/base . So that ,

$\sf\dashrightarrow tan45^{\circ}= \dfrac{AC}{AB}\\\\\sf\dashrightarrow tan45^{\circ}= \dfrac{35m}{x} \\\\\sf\dashrightarrow 1 =\dfrac{35m}{x} \\\\\sf\dashrightarrow x = 35*1 \\\\\sf\dashrightarrow \boxed{\pink{\sf x = 35 m }}$

Hence the horizontal distance is 35 m .

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$\qquad\qquad\tiny\boxed{\red{\textsf{\textbf{ Hence the Horizontal Distance is 35m. }}}}$

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