from a top of the light house 200m high the angle depression of two ship which are due to the south of the observed are 60°and 30° find the distance between the two ship
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Answer:
Let D and C be given ships and AB be the lighthouse.
Let Height of light house is AB=h
In △BAC, we have:
tan45∘=BCAB
1=BCAB ⟹AB=BC
so, BC=h ... (1)
In triangle ADB,
tan30∘=BDAB
31=BC+200h
31=h+200h [Using (1)]
h+200=h3
h(3−1)=200
h=3−1200 m
OR,
By rationalization and simplification, we get,
h=100(3+1) m
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