Question

From a top of the tower 40 m high, a body is thrown vertically upwards with a velocity of 10 m per second. How much time does the body takes to reach the ground. What is its velocity just before it hits the ground. (g=10 m per second) ​

Answer 1

Answer:

HAY MATE UR ANSWER IS HERE

HEIGHT OR DISTANCE =40M OR

S=40M

U=10

V=0

V IS 0 BECOZ AFTER GOING UPWARDS THE BODY COMES DOWN AT REST

NOW FIND THE ACCELERATION

THE FORMULA IS

V*2-U*2=2AS

0-100=2×A×40

-100= 80A

-100/80=A

A=-5/4

NOW FIND TIME BY USING FORMULA

A=V-U/T

-5/4=0-10/T

-5/4T=-10

T= 8M^S*-

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