from a tower of 120 m high, the angle of depression of a car is 30 find how far the car is from the tower
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Answered by
0
Answer:
Find an answer to your question from the top of a 120m high ... base of tower with angles of depression as 60° and 45 °.find the ... Now, distance between the cars = BD
Step-by-step explanation:
The angle of elevation of the top and angle of depression of the bottom of the first tower as ... Find the height of the two towers. ... The horizontal distance between two towers is 120 m.
Answered by
0
Step-by-step explanation:
Let AB and CD are two towers.
BD=120m=EC, ∠ACE=30
o
, ∠CBD=24
o
.
In right angle △CBD,
tan24
o
=
BD
CD
=
120
CD
CD=120×0.4452
=53.42m
In right angle △ACE,
tan30
o
=
EC
AE
=
120
AE
AE=120×0.5773
=69.28m
AB=AE+EB
=AE+CD [EB=CD]
=69.28+53.42
=122.7m
Height of 1
st
tower is 122.7m and 2
nd
tower is 53.42m.
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