From a triangle of vertices A,B and C of AB 6 cm and AC 10 cm find: a)sinA b)cos A, c)tan C,d)sec C,e)cot A,f)cosec A
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Step-by-step explanation:
by the Pythagoras theorem
AB^2+BC^2=AC^2
BC^2=AC^2-AB^2
BC^2=(10)^2-(6)^2
BC^2=100-36
BC=√(64)
BC=8cm
- sinA=BC/AC=8/10=4/5
- cosA=AB/AC=6/10=3/5
- tanC=AB/BC=6/8=3/4
- secC=AC/BC=10/8=5/4
- cotA=AB/BC=6/8=3/4
- cosecA=AC/BC=10/8=5/4
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