Question

from a uniform circular disc of mass M and radius R/2is removed in such a way that borh have comman tangent. find the distance if centre of mass of remaining part from the centre of original disc

Answer 1

The distance form the centre of mass is R/6.

Explanation:

Let the mass of the disc = M

Therefore, the mass of the removed part of disc, m = (M/R^2) x (R/2)^2 = M/4

Now the center of gravity of the resulting flat body.

R= [M x 0 – (M/4) x (R/2)] / (M-M/4)

= - (MR/8) / (3M/4)

= - R/6

Negative sign shows the opposite direction of center of gravity which lies at a distance of R/6 form the original centre of mass.

Hence the distance form the centre of mass is R/6.

Centre of mass and center of gravity​ ?

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Answer 2

Answer:

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