From a uniform disc of radius r and mass 9m a small disc of radius r/3 is removed
Answers
Answered by
10
Answer:
answer is 4MR^2
Explanation:
I remain = I axis + I removed
= 9MR^2/2+I removed
I removed= -[M(R/3)^2/2+M(2/3R)^2]
= -[MR ^2/18+4MR^2/9]
= -[9MR^2/18]
= -[MR^2/2]
I remain = 9MR^2/2+[-MR^2/2]
=8MR^2/2
=4MR^2
I hope this answer will help you!!!
Similar questions