from a vessel filled up with pure spirit to the brim, 2 litres of spirit was removed and 2 litres of water were added. after the solution was mixed, 2 litres of the mixture was poured off and again 2 litres of water was added. the solution was stirred again and 2 litres of mixture was removed and 2 litres of water was added. as a result the volume of water is increased by 3 litres than the volume of spirit remaining in it. how many litres of spirit and water was there in the vessel after the above procedure was carried out?
Answers
Given : A vessel filled up with pure spirit to the brim, 2 litres of spirit was removed and 2 litres of water were added. after the solution was mixed, 2 litres of the mixture was poured off and again 2 litres of water was added. the solution was stirred again and 2 litres of mixture was removed and 2 litres of water was added. as a result the volume of water is increased by 3 litres
To find : volume of spirit remaining in it. how many litres of spirit and water was there in the vessel after the above procedure was carried out
Solution:
Let say Volume of Spirit = S Litre
2 litres of spirit was removed and 2 litres of water were added
=> Spirit = S - 2 & water = 2 Litre
2 litres of the mixture was poured off and again 2 litres of water was added
Spirit = S - 2 - 2(S-2)/S = (S - 2)(1 - 2/S) = (S- 2)²/S
Water = S - (S- 2)²/S or 2 - 2*2/S + 2 = 4 - 4/S = 4(S - 1)/S
2 litres of the mixture was poured off and again 2 litres of water was added
Spirt = (S- 2)²/S - 2(S- 2)²/S² = ((S- 2)²/S) ( 1 - 2/S) = (S- 2)³/S²
Water = S - (S- 2)³/S² or 4(S - 1)/S - 2*4(S - 1)/S² + 2
S - (S- 2)³/S² = 3
=> S³ - (S - 2)³ = 3S²
=>S³ = 3S² + (S - 2)³
=> S³ = 3S² + S³ - 8 - 6S(S - 2)
=> 0 = 3S² - 8 - 6S² + 12S
=> 3S² - 12S + 8 = 0
S = (12 ± √48)/6 =( 12 ± 4√3)/6
=> S = 3.154 or 0.845 (not possible as water increased by 3 litres)
initial Spirit = 3.154 Litre
Final Spirit = 0.154 Litre
Water = 3 Litre
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