Math, asked by akoisharma, 8 days ago

From a well shuffled deck of 52 cards, one card is
drawn. Find the probability of getting.

a) 5 of black

Answers

Answered by ushasrikanth2014
0

Answer:

No. of cards in pack =52

Solution(i):

No. of kings of red suit =2

Therefore,

2

C

1

( Selecting 1 out of 2 items) times out of

52

C

1

( Selecting 1 out of 52 items) a king of red suit is picked.

Let E be the event of getting a king of red suit from pack

We know that, Probability P(E) =

(Total no.of possible outcomes)

(No.of favorable outcomes)

=

52

C

1

2

C

1

=

52

2

=

26

1

Solution(ii):

No. of face cards =12

Therefore,

12

C

1

( Selecting 1 out of 12 items) times out of

52

C

1

( Selecting 1 out of 52 items) a face card is picked.

Let E be the event of getting a face card from the pack

We know that, Probability P(E) =

(Total no.of possible outcomes)

(No.of favorable outcomes)

=

52

C

1

12

C

1

=

52

12

=

13

3

Solution(iii):

No. of red face cards =6

Therefore,

6

C

1

( Selecting 1 out of 6 items) times out of

52

C

1

( Selecting 1 out of 52 items) a red face card is picked.

Let E be the event of getting a red face card from the pack

We know that, Probability P(E) =

(Total no.of possible outcomes)

(No.of favorable outcomes)

=

52

C

1

6

C

1

=

52

6

=

26

3

Solution(iv):

No. of queens of black suit =2

Therefore,

2

C

1

( Selecting 1 out of 2 items) times out of

52

C

1

( Selecting 1 out of 52 items) a queen of black suit is picked.

Let E be the event of getting a queen of black suit from pack

We know that, Probability P(E) =

(Total no.of possible outcomes)

(No.of favorable outcomes)

=

52

C

1

2

C

1

=

52

2

=

26

1

Solution(v):

No. of jacks of heart =1

Therefore,

1

C

1

( Selecting 1 out of 1 items) times out of

52

C

1

( Selecting 1 out of 52 items) a jack of hearts is picked.

Let E be the event of getting a jack of hearts from pack

We know that, Probability P(E) =

(Total no.of possible outcomes)

(No.of favorable outcomes)

=

52

C

1

1

C

1

=

52

1

Solution(vi):

No. of spades =13

Therefore,

13

C

1

( Selecting 1 out of 13 items) times out of

52

C

1

( Selecting 1 out of 52 items) a spade is picked.

Let E be the event of getting a spade card from pack

We know that, Probability P(E) =

(Total no.of possible outcomes)

(No.of favorable outcomes)

=

52

C

1

13

C

1

=

52

13

=

4

1

Answered by Adi935
1

1/26 or 3.84

please mark this as the brainliest answer

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