Question

From a well shuffled pack of 52 cards, a card is drawn at random. Find the probability that it is either a heart or a king.​

Answer 1

Answer:

I guess it is heart becuase there are more hearts in a pack of cards

Hope it helps

Answer 2

Answer:

$\blue\bigstar \sf Probability \:that \:the \:card \:drawn\: is \:either \:a \:heart \:or \:a\: king = \dfrac{16}{52}$

    SOLUTION    

Total Number of cards = 52.

Total number of Heart = 13.

Total Number of Kings = 4.

$\red\bigstar \sf Probability\: of \:an\: Event =\dfrac{Number\:of\: Favorable \:events}{Total \:number\: of \:events}$

Probability that the card drawn is a King

Number of Favorable Events = 4.

Total Number of Events = 52.

$\bigstar\sf Probability = \dfrac{4}{52} = \dfrac{1}{13}$

Probability that the card drawn is a Heart

Number of Favorable Events = 13.

Total Number of Events = 52.

$\bigstar \: \sf Probability = \dfrac{13}{52}$

Probability that it is either a heart or a king.​

$\blue\bigstar$ Probability that the card drawn is either a heart or a king = Probability that the card drawn is a King + Probability that the card drawn is a Heart - Probability of getting the king of Heart.

$\sf Probability \:that \:the \:card \:drawn\: is \:either \:a \:heart \:or \:a\: king = \dfrac{1}{4} + \dfrac{1}{13} - \dfrac{1}{52}$

{LCM of 4 , 13 and 52  = 52.}

$\sf Probability \:that \:the \:card \:drawn\: is \:either \:a \:heart \:or \:a\: king = \dfrac{13+4-1}{52}$

$\sf Probability \:that \:the \:card \:drawn\: is \:either \:a \:heart \:or \:a\: king = \dfrac{16}{52}$