Question

from a well shuffled pack of 52 playing card is drawn at random. find the probability, that it is a)an ace b)4 of diamond c)red card

Answer 1

no of cards = n = 52
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a) no of ace = m = 4

P(ace) = m/ n

= 4/52  = 1/13
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b) no of 4 of diamond = 1 = m

p(4 of diamond) = m/n
 
= 1/52
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c) no of red cards = 26 = m

P(red card) = m/n 

= 26/52 = 1/2
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Answer 2

1) total no. of cards = 52...
ace cards = 13
so that, the probabilty = 13/52

2) no. of 4 diamonds = 1
so that the probability = 1/52

3) no. of red cards = 26
and the probability = 26/52 = 1/2