from a window 15 M high above the ground in a street the angle of the elevation and depression of the top and the foot of the another house on the opposite side of the street are 30° and 45° respectively find the height of the opposite house also find the horizontal distance between the two houses
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Step-by-step explanation:
Let the image be like this ( the height is 15 m not 10 )
x = 30 and y = 45
In ΔABD,
BD = 15 M
SO TAN 45 = BD/AB
1= BD/AB
AB = 15 M
In ΔABC
TAN 30 = BC/AB
1/√3= H/15
H = 15/√3 = 5√3 M
Height of opposite house = 15 + 5√3 = 5 ( 3 + √3 )m
Distance between the two houses = 15m
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