From a window , 60m high above the ground, of a house in a street, the angles of elevation and deppression of the top and foot of another house on the opposite side of the street are 60 deg & 45 deg respectively. Show that the height of the opposite house is 60(1 root 3)metres.
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The distance between the two houses will be tan45=60/distance between...
Therefore distance between =60 meters
And also it is some height of the building because in a rectangle opposite sides are equal
Tan60=some unknown height of the building /60
Which is equal to 60root3
Then total height of the building =60+60roor3
If we take 60 common we get 60(1+root3)mts
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