from adjoining figure, find X+Y+Z
Attachments:
Answers
Answered by
12
we have,
angle BAD +angle BAC = 180 degrees
=> x + 70 = 180
=> x = 110
similarly,
60 + y = 180
=> y = 120
now, using angle sum property in triangles, we get,
70 + 60 + angle ABC = 180
=> Angle ABC = 50
thus, z + angle ABC = 180
=> z + 50 = 180
=> z = 130
HENCE, X + Y + Z = 110 + 120 + 130
= 360
HOPE THIS HELPS U
HAVE A GREAT DAY
angle BAD +angle BAC = 180 degrees
=> x + 70 = 180
=> x = 110
similarly,
60 + y = 180
=> y = 120
now, using angle sum property in triangles, we get,
70 + 60 + angle ABC = 180
=> Angle ABC = 50
thus, z + angle ABC = 180
=> z + 50 = 180
=> z = 130
HENCE, X + Y + Z = 110 + 120 + 130
= 360
HOPE THIS HELPS U
HAVE A GREAT DAY
Answered by
4
Solution:
In the given figure, DAC is a straight line,so
x+70° = 180°
=> x = 110°
Similarly, BCF is a straight line
y +60°=180°
=> y= 120°
Now, in the ∆ABC ,
<A+<B+<C = 180[Sum of all the angles of a ∆]
=> 70° + <B + 60°= 180°
=> <B + 130° = 180°
=> <B = 50°
Now, ABE is a straight line,
<B + z = 180°
=> 50° + z = 180°
=> z = 130°
Now,
APQ : x+y+z = 110°+120°+130° = 360°
Hope this helps you dear friend ‼️
In the given figure, DAC is a straight line,so
x+70° = 180°
=> x = 110°
Similarly, BCF is a straight line
y +60°=180°
=> y= 120°
Now, in the ∆ABC ,
<A+<B+<C = 180[Sum of all the angles of a ∆]
=> 70° + <B + 60°= 180°
=> <B + 130° = 180°
=> <B = 50°
Now, ABE is a straight line,
<B + z = 180°
=> 50° + z = 180°
=> z = 130°
Now,
APQ : x+y+z = 110°+120°+130° = 360°
Hope this helps you dear friend ‼️
Anonymous:
yes ?
Similar questions