Math, asked by Atharva1317s, 10 months ago

From amongst 2000 literate individuals of a town 60% read newspaper A , 55% read newspaper B, 20% read nither A nor B . How many individuals read both newspapers A as well as B​

Answers

Answered by syedtahir20
0

The require answer is 700.

As per the question we need to find the how many individuals read both newspapers A as well as B.

The given is From amongst 2000 literate individuals of a town 60% read newspaper A , 55% read newspaper B, 20% read nither A nor B .

out of total.of 100%

if 20% didn't read so 80% who read either A or B or Both

so 35% read both (60+55-80= 35)

2000 × 35/100 = 700

Hence the require answer is 700.

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Answered by tripathiakshita48
0

700 individuals out of the 2000 literate individuals in the town read both newspapers A and B.

To find the number of individuals who read both newspapers A and B, we need to consider the given information about the percentage of individuals who read each newspaper. Out of the 2000 literate individuals in the town, 60% read newspaper A and 55% read newspaper B, while 20% read neither of the newspapers.

First, we calculate the total percentage of individuals who read either newspaper A, B, or both, which is 80% (100% - 20%). Then, we subtract the percentage of individuals who read only one newspaper from the total to get the percentage of individuals who read both newspapers. The percentage of individuals who read both newspapers is

35% (60% + 55% - 80%).

Finally, to get the total number of individuals who read both newspapers, we multiply the percentage by the total number of individuals and divide by 100. The result is 700 (2000 × 35/100).

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