From an acute angle thita show that (sin thita-cos thita) (cos thita - sec thita)=1÷tan thita + cot thita?
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Answer:
Ccasec9-sind JsCO-403 2J
Jan@-Coa
dh.S (cesaa-sin 82 (Sac9-Cas 9
Sin 0
LSin 1Cas-0)
G Sin 0 Cas 0
Los 0/Sin20
Sin
COsO
dHS Sino. cos0
HS
dang+_(61
sin@asat Cas sin
sin t 6a
Sin Cos
SinO Cos2
Sin t (6s9
HS RHS-
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