From an aeroplane ata height of 600m above the lecel grpund the angles of depression of two ships are observed as 60 degree and 30 degree
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From an aeroplane at a height of 600 m above the level ground, the angles of depression of two ships are observed as 60° and 30° coming towards it. Find the distance between two ships.
Solution
→ tan60° = 600/x
→ √3 = 600/x
→ x = 600/√3 or 200√3
→ tan30° = 600/(AB + x)
→ 1/√3 = 600/(AB + 200√3)
→ AB + 200√3 = 600√3
→ AB = 400√3
- Value of √3 = 1.732
→ AB = 400 × 1.732
→ AB = 692.8 m
Hence distance between two ships (length of AB) is 692.8 m.
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