Question

from an elevated. a stone is projected vertically upwards when the sun reaches the distance at below a

Answer 1

MAY BE YOU HAVE WRITTEN HALF OF THE QUESTION FULL QUESTION IS

From an elevated point 'A', a stone is projected vertically upwards when stone reaches a distance 'h' below A, its velocity is double of what it was at height 'h' above A. show that greatest height attained by stone is5/3 h

For this question the answer is

Given :

Distance=h

Initial velocity of stone =u

Velocity at point B , "h" above A is :

Vb²=u²-2gh

Vb=√(u2-2gh)

velocity at point C below "h"

Vc²=u2-2g(-h)

vc²=u2+2ghvc

=√(u2+2gh)

But according to given :

Vc²=4Vb²

(√(u1+2gh)²=4√(u2-2gh)²

u²+2gh=4u²-8gh

u²=10gh/3

Maximum height attained by stone:

Hmax=u²/2g

=10gh /3x2g=5h/3

∴Maximum height attained by stone is 5h/3