Question

From an elevated point A , a stone is projected vertically upwards when the stone reaches a distance h below A, its velocity is double of what it was at a height h above A the greatest height attained by the stone is​

Answer 1

HOPE ITS HELPFUL FOR YOU

Answer 2

Answer:

Let initial velocity = u

Therefore at point 'P', AP = h

$v {p}^{2} - {u}^{2} = - 2gh$

At point Q, V₂²-u² = 2 (-g)(-h) = +2gh

As VQ = 2Vp, so

4Vp²-u² = 2gh

4[u²-2gh]-u² = 2gh

²-8gh-u² = 2gh 4u².

3u² = 10 gh

u² = (10/3)gh

But 0²-u²=-2gH-(4) \2gH = (10/3)gh

H = (5/3)h