From an elevated point P, a stone is projected vertically upwards. When the stone reaches a distance
h below P, its velocity is double of its velocity at a height h above P. The greatest height attained by the
stone from the point of projection P is
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11th
Physics
Motion in a Plane
Projectile Motion
From an elevated point P , ...
PHYSICS
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Asked on October 15, 2019 by
Vaishakhi Pasupuleti
From an elevated point P, a stone is projected vertically upwards. When the stone reaches a distance h below P, its velocity is double of its velocity at a height h above P. The greatest height attained by the stone from the point of projection P is :
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ANSWER
From equations of motions, we know
v
2
=u
2
−2gh ...(i)
Here, v=2v, so
(2v)
2
=u
2
+2gh ...(ii)
Now, on adding Eqs. (i) and (ii), we get
5v
2
=2u
2
u
2
=
2
5
v
2
...(iii)
On subtracting Eq. (i) in Eq. (ii), we get
3v
2
=4gh
v
2
=
3
4
gh ...(iv)
And we know that the
H=
2g
u
2
So, here H=
2g
2
5
v
2
=
2g
2
5
(
3
4
gh
)
H=
3
5
h