Question

from an external point P A and PB are two tangents with circle if angle PAB =50° than find angle AOB​

Answer 1

Answer:

40'

Step-by-step explanation:

because sum of it 90' so it will be 40'

Answer 2

Answer:

in ∆pab given that

angle PAB is 50°

and angle PAO=90°

PAO= angle PAB+OAB

90=50+OAB

then angle OAB=40°

NOW In trianlge OAB

OA=OB

THUS angle OAB and oba will be equal

then in triangle OAB

OAB+oba+ aob =180

40+40+aob=180

aob=180+80

aob=100°