Question

From an external point P, tangent PA = PB are drawn to a circle with center O. If PAB = 50°.[Find AOB.}

Answer 1

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______Here's your Answer _______

Answer 2

∠PAB = 50°

∠PBA = 50° (as PA = PB)

⇒ 50 + 50 + ∠P = 180°  (angle sum property)

⇒ ∠P = 80°

Also, ∠O + ∠P = 180°

⇒ ∠O = 180° – 80° = 100