Question

from an external point p, tangents PA and PB are drawn to a circle with centre o. if anglePAB=50degree, then findangle AOB​

Answer 1

Answer:

=50°. Now, we know that tangents to a circle from the same point are equal in length. Thus, ∆PAB is an isosceles triangle. Also, we know that angle in between two tangents is supplementary to the angle subtended by the tangents at the centre

Answer 2

The answer is in the attatchment.

.

.

.

.

Stay safe