from an external point P tangents PA and PB are drawn to a circle with Centre O if Angle P A B equal to 50 degree then find angle aob
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Angle PAB can not be 50°. It will be always be 90°.
If Angle APB be 50°, then Angle AOB be -
Angle AOB = 360° - Angle ( APB + PAO + PBO )
= 360° - Angle ( 50° + 90° + 90°)
= 360° - 230°
= 130°
If Angle APB be 50°, then Angle AOB be -
Angle AOB = 360° - Angle ( APB + PAO + PBO )
= 360° - Angle ( 50° + 90° + 90°)
= 360° - 230°
= 130°
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