Question

From an external point P, tangents PA and PB are drawn to a circle with centre O. If angle PAB = 50 degree, then find angle AOB. There is no figure with this question , don't put silly answers and the question is totally right.

Answer 1

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Answer 2

130 degree because ang. PAB=50degree OA perpendicular pA and OB perpen. PB by using theorem both are 90 degree and PAOB Is a quadrilateral so AOB = 360-PAB+OBP+OAP