Question

from an external point P tangents PA and PB are drawn to a circle.From a point Q on major arc AB, perpendiculars are drawn to AB, PA and PB.Prove that the perpendicular to AB is the mean proportional between the other two perpendiculars.​

Answer 1

Step-by-step explanation:

From figure,

CA is perpendicular to AP and CB is perpendicular to BP

Again AC = BC = 4 (radius of the circle)

Also AP = PB = (Tangents from point P)

So, BPAC is a square.

=> AP = PB = BC = CA = 4 cm

So, length of tangents are 4 cm each

therefore option B will be the answer.

Answer 2

Answer:

thanks for free points