From an external point P, two tangents PA and PB are drawn to a circle with centre O such that ∠APB = 50°, then ∠OAB is equal to:
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Given : A circle with centre O, an external point P and two tangents PA and PB to the circle, where A and B are points of contact (Fig.). Hence, ∠APB = 2 ∠OAB
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