Question

from an external point P two tangents PA and PB are drawn to a circle with Centre O at one point E on the circle tangent is drawn which intersect PA and PB at C and D respectively if PA equal to 10 cm find the perimeter of the triangle PCD

Answer 1

AP=PB=10cm

AC=CE

BD=DE

AP=AC+CP

   =CE+CP

    =10cm

PB=BD+DP

    =DE+DP

     =10cm

Perimeter of triangle PCD= CP+CD+DP

                                          = CP+CE+DE+DP

                                          = 10 +10cm = 20cm

Answer 2

Answer:

perimeter of Triangle PCD = 20 CM.

Step-by-step explanation:

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