Question

From an external point Q, the length of the tangent to a circle is 5 cm and
the distance of Q from the centre is 8 cm. The radius of the circle is
39 cm
3 cm
(A)
(B)
(C)
(D)
39 cm
7 cm​

Answer 1

Answer: √39

Step-by-step explanation:

As it is given that lenght of tangent is 5 cm .

And the distance of external point Q is 8 cm.

We know that angle between tangent and radius is 90° . Hence we apply Pythagoras theoram.

That 5^2 + x^2(where x is the radius) = 8^2 .

Since we get x =√39.

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Answer 2

Answer:

Step-by-step explanation:

√39 CM