Question

From an external point two tangents to a circle are drawn. The chord passing through the points of contact subtends an angle72° at the centre. The angle between the tangents is?

Answer 1

find angle x
we know that sum of all angle of quadrilateral is 360°

Answer 2

Answer:

108°

Step-by-step explanation:

From figure , OA = OB = radii of circle

Given , ∠AOB = 72°;

∠OBP = ∠OAP = 90°

In ∠OAB,

∠OAB = ∠OBA

∴ 2 ∠OAB = 180° – 72° = 108°

⇒ ∠OAB = 108°/2= 54°

∴ ∠PBA = ∠PAB = 90° – 54° = 36°

∴ ∠BPA = 180° – 2 × 36°

∠BPA = 180° – 72° = 108°