From an extrnal point p, tangents pa and pb are drawn to a circle with centre o. If angle PAB=50 degree then find angle aob.
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In tri. PAB, PA=PB (tangents from the same external point).
so, angle APB=180°-2*50°=180°-100°=80°
AS ANGLE aob +ANGLE PAB=180°
angle AOB = 100°
so, angle APB=180°-2*50°=180°-100°=80°
AS ANGLE aob +ANGLE PAB=180°
angle AOB = 100°
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