Math, asked by botweychristian99, 10 months ago

From an urn containing 3 white and 2 black balls, two balls are drawn one after the other without replacement. What is the probability that the first ball drawn is white and the second black? ​

Answers

Answered by Anonymous
1

Answer:

Step-by-step explanation:

Number of balls is 5 with 2 black balls. The first ball is drawn. Probability that it is black is 2/5. This ball is not returned. The numbers of balls in the box is now 4 with 1 black ball. Second ball is drawn and probability of its being black is 1/4. Hence, the required probability is

2/5×1/4=1/10 is the answer.

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Answered by coolopedia
2

Answer:

6/25

Step-by-step explanation:

GIVEN: okay so an urn contains 3 white balls and 2 black balls .... 2 balls are drawn each time..

Possibility: 1]first one is white and the second one is black

SOLUTION:

n(u)=5

no. of white balls=3

no. of black balls = 2

OKAY so probability of white balls= 3

                                                          5

now black balls = 2

                             5

hence =  3/5   *    2/5    =    6/25

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