Question

from and external point Tangent pt is drawn to circle whose centre is o. if OT =29 cm and PT =21cm, determine the radius of the circle

Answer 1

(OT)^2=(PT)^2+(OP)^2
(29)^2=(21)^2+(OP)^2
841=441+(OP)^2
841-441=(OP)^2
400=(OP)^2
(OP)^2=400
OP=20,
So radius is 20cm.

Answer 2

Answer:

OT)^2=(PT)^2+(OP)^2

(29)^2=(21)^2+(OP)^2

841=441+(OP)^2

841-441=(OP)^2

400=(OP)^2

(OP)^2=400

OP=20,

So radius is 20cm.

Step-by-step explanation: