Question

from chapter : congruence of triangle

please answer question no. 6 and 7​

Answer 1

Answer:

Answer of question no. 7

in triangle PQR and Triangle PSR

PQ. = PS. { given }

angle QPR = angle SPR. { PR bisects angle P }

PR = PR. { common }

therefore,

triangle PQR is congruent to triangle PSR

So, QR = SR.

{ corresponding part of congruent triangle}

Answer 2

Answer:

6

Step-by-step explanation:

We know that pq = rs and qr =sp. than ∆pqr and ∆psr pq = rs (given), qr = sp (given) and pr = pr (by common side) than ∆ pqr congruent ∆psr ( by sss ) it is prove