Question

from chapter exponent and radical

Answer 1

that's your answer that is -5/3

Answer 2

We can write the above equation as
(3^2)^x * 3^2 * (3^ -x/2)^ -2 = 1/3^3
3^2x * 3^2 * 3^ x = 3^-3
3^(2x + 2 + x ) = 3^ -3
As the base is equal , so
2x+2+x = -3
3x = -3-2 = -5
x = -5/3.
So, the value of x = -5/3.

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