Question

from chapter Logarithms​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

$\frac{1}{ log_{a}(bc) + 1} + \frac{1}{ log_{b}(ca) + 1} + \frac{1}{ log_{c}(ab) + 1 }$

$1 \: can \: written \: as \: 1 = log_{a}(a) \\ = \frac{1}{ log_{a}(abc) } + \frac{1}{ log_{b}(abc) } + \frac{1}{ log_{c}(abc) } \\ = log_{abc}(a) + log_{abc}(b) + log_{abc}(c) \\ log_{abc}(abc) = 1$

hope it's helpful to you and all