Question

from chapter understanding quadrilaterals....please answer as soon as possible ​

Answer 1

Answer:

$△ABC \: and \: △ADC \: are \: two \: equilateral \: triangles \: on \: a \: common \: base \: AC. \\ Since \: all \: the \: sides \: of \: equilateral \: triangles \: are \: equal \\ ⟹AB=BC=AC=AD</p><p> \\ Now \: in \:△ABC \\ ∠BAC=∠ACB=∠ABC(Equilateral \: triangle \: has \: all \: angles \: equal</p><p></p><p> \\ ⟹∠BAC=∠ACB=∠ABC=60...(1) \\ Now \: in \: △ADC \\ ∠ADC=∠DCA=∠CAD=60....(2) \\ In \: □ABCD \\ ∠BAD=∠BAC+∠CAD \\ ⟹∠BAD=60+60=120[From(1)and(2)] \\ Also,∠BCD=∠BCA+∠ACD \\ ⟹∠BCD=60+60=120[From(1)and(2)] \\ Also∠ABC=∠ADC=60 \\ Since∠BAD=∠BCDand \\ ∠ABC=∠ADCand \\ AB=BC=AD=CD \\ Hence \: the \: quadilateral \: is \: a \: rhombus \: as \: it \: have \: all \: the \: sides \: and \: opposite \: angles \: equal</p><p></p><p></p><p>$

Answer 2

Step-by-step explanation:

above answer is right hope it helps ☺️