Question

From class 11
Motion in 1D
Q. the position of a moving object is given by x=8t^2 where t is in second. what is the velocity and acceleration at t=4 sec?​

Answer 1

Answer:

v = dx /dt = d( 8t^2)/ dt = 8*2t = 16 t

So, v at 4 sec = 16*4 = 64 m/s

And,

a =dv /dt = d(16t)/dt  = 16 m/s^2

So, a at 4 sec = 16 m/s^2

Answer 2

Answer:

v=dx/dt = d( 8t^2)/ dt = 8*2t = 16 t So, v at 4 sec = 16*4 = 64 m/s

And,

a dv/dt = d(16t)/dt = 16 m/s^2

So, a at 4 sec = 16 m/s^2