From crystal field theory , find out the number of unpaired electrons in the low - spin complex [Co(CN)6]3-
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SOLUTION :-
1) The complex has an octahedral shape
The aqua ligand (H2OH2O) is typically regarded as weak-field ligand.
2) The d electron configuration for CoCo is d6d6
3) The splitting energy is small.
Therefore, the complex is expected to be high spin.
1) The complex has an octahedral shape
The aqua ligand (H2OH2O) is typically regarded as weak-field ligand.
2) The d electron configuration for CoCo is d6d6
3) The splitting energy is small.
Therefore, the complex is expected to be high spin.
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1) The complex has an octahedral shape
The aqua ligand (H2OH2O) is typically regarded as weak-field ligand.
2) The d electron configuration for CoCo is d6d6
3) The splitting energy is small.
Therefore, the complex is expected to be high spin.
The aqua ligand (H2OH2O) is typically regarded as weak-field ligand.
2) The d electron configuration for CoCo is d6d6
3) The splitting energy is small.
Therefore, the complex is expected to be high spin.
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