Question

From each corner of a square of side 3 cm, a quadrant of a circle of radius 1 cm is cut and also a circle
of diameter 2 cm is cut as shown in the given figure. Find the area of the remaining part of the
square
(user r=3.14)​

Answer 1

Answer:

Area of shaded region = Area of square ABCD − Area of 4 quadrants − Area of circle with diameter 2 cm

Area of shaded region = Area of square ABCD − Area of 4 quadrants − Area of circle with diameter 2 cmArea of square =4×4=16cm

Area of shaded region = Area of square ABCD − Area of 4 quadrants − Area of circle with diameter 2 cmArea of square =4×4=16cm 2

Area of shaded region = Area of square ABCD − Area of 4 quadrants − Area of circle with diameter 2 cmArea of square =4×4=16cm 2

Area of shaded region = Area of square ABCD − Area of 4 quadrants − Area of circle with diameter 2 cmArea of square =4×4=16cm 2 Area of sector =

Area of shaded region = Area of square ABCD − Area of 4 quadrants − Area of circle with diameter 2 cmArea of square =4×4=16cm 2 Area of sector = 360

Area of shaded region = Area of square ABCD − Area of 4 quadrants − Area of circle with diameter 2 cmArea of square =4×4=16cm 2 Area of sector = 360θ

Area of shaded region = Area of square ABCD − Area of 4 quadrants − Area of circle with diameter 2 cmArea of square =4×4=16cm 2 Area of sector = 360θ

Area of shaded region = Area of square ABCD − Area of 4 quadrants − Area of circle with diameter 2 cmArea of square =4×4=16cm 2 Area of sector = 360θ ×π×r

Area of shaded region = Area of square ABCD − Area of 4 quadrants − Area of circle with diameter 2 cmArea of square =4×4=16cm 2 Area of sector = 360θ ×π×r 2

Area of shaded region = Area of square ABCD − Area of 4 quadrants − Area of circle with diameter 2 cmArea of square =4×4=16cm 2 Area of sector = 360θ ×π×r 2

Area of shaded region = Area of square ABCD − Area of 4 quadrants − Area of circle with diameter 2 cmArea of square =4×4=16cm 2 Area of sector = 360θ ×π×r 2 Area of 4 quadrants =4×

Area of shaded region = Area of square ABCD − Area of 4 quadrants − Area of circle with diameter 2 cmArea of square =4×4=16cm 2 Area of sector = 360θ ×π×r 2 Area of 4 quadrants =4× 360

Area of shaded region = Area of square ABCD − Area of 4 quadrants − Area of circle with diameter 2 cmArea of square =4×4=16cm 2 Area of sector = 360θ ×π×r 2 Area of 4 quadrants =4× 36090

Area of shaded region = Area of square ABCD − Area of 4 quadrants − Area of circle with diameter 2 cmArea of square =4×4=16cm 2 Area of sector = 360θ ×π×r 2 Area of 4 quadrants =4× 36090

Area of shaded region = Area of square ABCD − Area of 4 quadrants − Area of circle with diameter 2 cmArea of square =4×4=16cm 2 Area of sector = 360θ ×π×r 2 Area of 4 quadrants =4× 36090 ×π×1×1

Area of shaded region = Area of square ABCD − Area of 4 quadrants − Area of circle with diameter 2 cmArea of square =4×4=16cm 2 Area of sector = 360θ ×π×r 2 Area of 4 quadrants =4× 36090 ×π×1×1 =3.14cm

Area of shaded region = Area of square ABCD − Area of 4 quadrants − Area of circle with diameter 2 cmArea of square =4×4=16cm 2 Area of sector = 360θ ×π×r 2 Area of 4 quadrants =4× 36090 ×π×1×1 =3.14cm 2

Area of shaded region = Area of square ABCD − Area of 4 quadrants − Area of circle with diameter 2 cmArea of square =4×4=16cm 2 Area of sector = 360θ ×π×r 2 Area of 4 quadrants =4× 36090 ×π×1×1 =3.14cm 2

Area of shaded region = Area of square ABCD − Area of 4 quadrants − Area of circle with diameter 2 cmArea of square =4×4=16cm 2 Area of sector = 360θ ×π×r 2 Area of 4 quadrants =4× 36090 ×π×1×1 =3.14cm 2 Area of circle=π×r

Area of shaded region = Area of square ABCD − Area of 4 quadrants − Area of circle with diameter 2 cmArea of square =4×4=16cm 2 Area of sector = 360θ ×π×r 2 Area of 4 quadrants =4× 36090 ×π×1×1 =3.14cm 2 Area of circle=π×r 2

Area of shaded region = Area of square ABCD − Area of 4 quadrants − Area of circle with diameter 2 cmArea of square =4×4=16cm 2 Area of sector = 360θ ×π×r 2 Area of 4 quadrants =4× 36090 ×π×1×1 =3.14cm 2 Area of circle=π×r 2 =π×1×1

Area of shaded region = Area of square ABCD − Area of 4 quadrants − Area of circle with diameter 2 cmArea of square =4×4=16cm 2 Area of sector = 360θ ×π×r 2 Area of 4 quadrants =4× 36090 ×π×1×1 =3.14cm 2 Area of circle=π×r 2 =π×1×1 =3.14cm

Area of shaded region = Area of square ABCD − Area of 4 quadrants − Area of circle with diameter 2 cmArea of square =4×4=16cm 2 Area of sector = 360θ ×π×r 2 Area of 4 quadrants =4× 36090 ×π×1×1 =3.14cm 2 Area of circle=π×r 2 =π×1×1 =3.14cm 2

Area of shaded region = Area of square ABCD − Area of 4 quadrants − Area of circle with diameter 2 cmArea of square =4×4=16cm 2 Area of sector = 360θ ×π×r 2 Area of 4 quadrants =4× 36090 ×π×1×1 =3.14cm 2 Area of circle=π×r 2 =π×1×1 =3.14cm 2

Area of shaded region = Area of square ABCD − Area of 4 quadrants − Area of circle with diameter 2 cmArea of square =4×4=16cm 2 Area of sector = 360θ ×π×r 2 Area of 4 quadrants =4× 36090 ×π×1×1 =3.14cm 2 Area of circle=π×r 2 =π×1×1 =3.14cm 2 ∴ Area of shaded region =16−6.28 =9.72cm2

i hopes it helps u!!!