Math, asked by jebinsultana451, 2 months ago

From each corner of a square of side 4 c.m , a circle of diameter 2 c.m is cut as shown in the figure below. Find the area of the remaining portion of the square​

Answers

Answered by professionalhelper65
1

Answer:

For this you need to subtract area of 4 quadrants from area of square as there are 4 circles and only a quadrant is inside the square of each circle.

Step-by-step explanation:

given that side of square is 4cm.

So area of square = a^2=16cm^2

Diameter of circle =2cm.

Radius of circle =1cm

Area of quadrant = 90 × 22 ×1×1

360. 7

=1 × 22 ×1×1 = 11

4. 7. 14

Area of 4 quadrants = 11 × 4 = 22

14. 7

Area of remaining portion = area of square-area of 4 quadrants

=16-22 = 16-3.14 = 12.86cm^2 ANS

7

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