Question

From each of the following equations, write down the:

(i) substance reduced (ii) substance oxidized

(a) PbS + 4H2O2 PbSO4 + 4H2O

(b) SO2 + 2H2S 2H2O + 3S

(c) MnO2 + 4HCl MnCl2 + 2H2O + Cl2

(d) ZnO + C Zn + CO

(e) H2S + Cl2 S + 2HCl

(f) CuO + H2 Cu + H2O​

Answer 1

Answer:

(a) PbS + 4H2O2 → PbSO4 + 4H2O

Substance reduced : H2O2

Substance oxidized : PbS

(b)  SO2 + 2H2S → 2H2O + 3S

Substance reduced : SO2

Substance oxidized : H2S

(c) MnO2 + 4HCl → MnCl2 + 2H2O + Cl2

Substance reduced : MnO2

Substance oxidized : HCl

(d) ZnO + C → Zn + CO

Substance reduced : ZnO

Substance oxidized : C

(e) H2S + Cl2 → S + 2HCl

Substance reduced : Cl2

Substance oxidized : H2S

(f) CuO + H2 → Cu + H2O​

Substance reduced : CuO

Substance oxidized : H2

Explanation: